GATE EE 2005 | GATE EE Year Wise Previous Years Questions

GATE EE 2005

MCQ (Single Correct Answer)

-0.6

Two networks are connected in cascade as shown in the Fig. With the usual notations the equivalent $$A,B,C$$ and $$D$$ constants are obtained. Given that, $$C$$ $$ = 0.025\angle {45^ \circ },$$ the value of $${Z_2}$$ is GATE EE 2005 Electric Circuits - Two Port Networks Question 4 English

GATE EE 2005 Electric Circuits - Two Port Networks Question 4 English

$$10\angle {30^ \circ }\Omega $$

$$40\angle - {45^ \circ }\,\,\Omega $$

$$1\,\,\Omega $$

$$0\,\,\Omega $$

GATE EE 2005

MCQ (Single Correct Answer)

-0.3

For the two port network shown in the Fig. the $$Z$$ $$-$$ matrix is given by GATE EE 2005 Electric Circuits - Two Port Networks Question 10 English

$$\left[ {\matrix{ {{Z_1}} & {{Z_1} + {Z_2}} \cr {{Z_1} + {Z_2}} & {{Z_2}} \cr } } \right]$$

$$\left[ {\matrix{ {{Z_1}} & {{Z_1}} \cr {{Z_1} + {Z_2}} & {{Z_2}} \cr } } \right]$$

$$\left[ {\matrix{ {{Z_1}} & {{Z_2}} \cr {{Z_1}} & {{Z_1} + {Z_2}} \cr } } \right]$$

$$\left[ {\matrix{ {{Z_1}} & {{Z_1}} \cr {{Z_1}} & {{Z_1} + {Z_2}} \cr } } \right]$$

GATE EE 2005

MCQ (Single Correct Answer)

-0.6

The $$RL$$ circuit of the figure is fed from a constant magnitude, variable frequency sinusoidal voltage source $${V_{IN.}}$$ At $$100Hz,$$ the $$R$$ and $$L$$ elements each have a voltage drop $${u_{RMS}}.$$ If the frequency of the source is changed to $$50Hz,$$ then new voltage drop across $$R$$ is GATE EE 2005 Electric Circuits - Sinusoidal Steady State Analysis Question 14 English

GATE EE 2005 Electric Circuits - Sinusoidal Steady State Analysis Question 14 English

$$\sqrt {{5 \over 8}} \,\,{u_{RMS}}$$

$$\sqrt {{2 \over 3}} \,\,{u_{RMS}}$$

$$\sqrt {{8 \over 5}} \,\,{u_{RMS}}$$

$$\sqrt {{3 \over 2}} \,\,{u_{RMS}}$$

GATE EE 2005

MCQ (Single Correct Answer)

-0.6

A coil of inductance $$10$$ $$H$$ resistance $$40\,\,\Omega $$ is connected as shown in Fig. After the switch $$S$$ has been in connection with point $$1$$ for a very long time, it is moved to point $$2$$ at $$t = 0.$$

For the value of $$R$$ obtained in the above question, the time taken for $$95\% $$ of the stored energy to be dissipated is close to

$$0.10$$ $$sec$$

$$0.15$$ $$sec$$

$$0.50$$ $$sec$$

$$1.0$$ $$sec$$

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