COMEDK 2025 Morning Shift | Gravitation Question 6 | Physics

The radius of earth is $R$ and acceleration due to gravity on its surface is $g$. The height at which the acceleration due to gravity becomes $\frac{g}{8}$ is:

$2 R$

$(2 \sqrt{2}-1) R$

$\sqrt{2} R$

$2 \sqrt{2} R$

COMEDK 2025 Morning Shift

MCQ (Single Correct Answer)

-0

A planet is 121 times heavier than moon and has a diameter 9 times that of moon. If the escape velocity on the planet is $v$, then the escape velocity on the moon will be:

$\frac{11 v}{3}$

$\frac{33 v}{8}$

$\frac{8 v}{33}$

$\frac{3 v}{11}$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

The acceleration due to gravity at pole and equator can be related as

$$g_e=g_p < g$$

$$g_e=g_p=g$$

$$g_e < g_p$$

$$g_e > g_p$$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

A satellite is revolving around the earth in a circular orbit with kinetic energy of $$1.69 \times 10^{10} \mathrm{~J}$$. The additional kinetic energy required for just escaping into the outer space is

$$3.38 \times 10^{10} \mathrm{~J}$$

$$1.69 \times 10^{10} \mathrm{~J}$$

$$0.89 \times 10^{10} \mathrm{~J}$$

$$1.35 \times 10^{10} \mathrm{~J}$$

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