COMEDK 2024 Morning Shift | Electrostatics Question 26 | Physics

Two metal spheres, one of radius $$\frac{R}{2}$$ and the other of radius $$2 \mathrm{R}$$ respectively have the same surface charge density They are brought in contact and separated. The ratio of their new surface charge densities is

$$2: 1$$

$$4: 1$$

$$1: 4$$

$$1: 2$$

COMEDK 2023 Morning Shift

MCQ (Single Correct Answer)

-0

When $$10^{19}$$ electrons are removed from a neutral metal plate, the electric charge on it is

$$-1.6 \mathrm{~C}$$

$$+1.6 \mathrm{~C}$$

$$10^{+19} \mathrm{~C}$$

$$10^{-19} \mathrm{~C}$$

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

Two point charges $$20 \mu \mathrm{C}$$ and $$-10 \mu \mathrm{C}$$ are separated by a distance of $$1 \mathrm{~m}$$ in air. At what point on the line joining the two charges, the electric potential is zero.

$$0.5 \mathrm{~m}$$ from the charge $$10 \mu \mathrm{C}$$

$$0.76 \mathrm{~m}$$ from the charge $$20 \mu \mathrm{C}$$

$$0.67 \mathrm{~m}$$ from the charge $$20 \mu \mathrm{C}$$

$$0.25 \mathrm{~m}$$ from the charge $$10 \mu \mathrm{C}$$

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

A spherical metal ball of density '$$\rho$$' and radius '$$r$$' is immersed in a liquid of density '$$\sigma$$'. When an electric field is applied in the upward direction the metal ball remains just suspended in the liquid. Then the expression for the charge on the metal ball is :

$$q=\frac{\left[\frac{4}{3} \pi r^3 \rho g\right]}{\sigma E}$$

$$q=\frac{\left[4 \pi r^3(\rho-\sigma) g\right]}{3 E}$$

$$q=\frac{\left[4 \pi r^2 \rho g\right]}{\sigma E}$$

$$q=\frac{\left[4 \pi r^2(\rho-\sigma) g\right]}{E}$$

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