1
COMEDK 2021
MCQ (Single Correct Answer)
+1
-0

The angle of projection with the horizontal in terms of maximum height attained and horizontal range is given by

A
$${\tan ^{ - 1}}\left( {{{2H} \over {3R}}} \right)$$
B
$${\tan ^{ - 1}}\left( {{{4R} \over {3H}}} \right)$$
C
$${\tan ^{ - 1}}\left( {{{4H} \over R}} \right)$$
D
$${\tan ^{ - 1}}\left( {{R \over H}} \right)$$
2
COMEDK 2020
MCQ (Single Correct Answer)
+1
-0

A body is projected vertically upwards. The times corresponding to height $$h$$, while ascending and while descending are $$t_1$$ and $$t _2$$ , respectively. Then, the velocity of projection is ($$g$$ is acceleration due to gravity)

A
$${{g\sqrt {{t_1}{t_2}} } \over 2}$$
B
$${{g({t_1} + {t_2})} \over 2}$$
C
$$g\sqrt {{t_1}{t_2}} $$
D
$${{g{t_1}{t_2}} \over {{t_1} + {t_2}}}$$
3
COMEDK 2020
MCQ (Single Correct Answer)
+1
-0

A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point

COMEDK 2020 Physics - Motion Question 7 English

A
D
B
A
C
B
D
C
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