COMEDK 2023 Morning Shift | Motion Question 3 | Physics

A body is projected vertically upwards. The times corresponding to height $$h$$ while ascending and while descending are $$t_1$$ and $$t_2$$, respectively. Then, the velocity of projection will be (take, $$g$$ as acceleration due to gravity)

$$\frac{g \sqrt{t_1 t_2}}{2}$$

$$\frac{g\left(t_1+t_2\right)}{2}$$

$$g \sqrt{t_1 t_2}$$

$$g \frac{t_1 t_2}{\left(t_1+t_2\right)}$$

COMEDK 2023 Morning Shift

MCQ (Single Correct Answer)

-0

A car starts from rest and accelerates uniformly to a speed of $$180 \mathrm{~kmh}^{-1}$$ in $$10 \mathrm{~s}$$. The distance covered by the car in this time interval is

500 m

250 m

100 m

200 m

COMEDK 2023 Morning Shift

MCQ (Single Correct Answer)

-0

A ball is projected horizontally with a velocity of $$5 \mathrm{~ms}^{-1}$$ from the top of a building $$19.6 \mathrm{~m}$$ high. How long will the ball take to hit the ground?

$$\sqrt{2} \mathrm{~s}$$

$$2 \mathrm{~s}$$

$$\sqrt{3} \mathrm{~s}$$

$$3 \mathrm{~s}$$

COMEDK 2023 Evening Shift

MCQ (Single Correct Answer)

-0

The nucleus of a helium atom travels along the inside of a straight hollow tube $$4 \mathrm{~m}$$ long which forms part of a particle accelerator. If one assumes uniform acceleration, how long is the particle in the tube if it enters at a speed of $$2000 \mathrm{~m} / \mathrm{s}$$ and leaves at $$8000 \mathrm{~m} / \mathrm{s}$$

$$0.6 \times 10^{-4}$$ s

$$4 \times 10^{-4} \mathrm{~s}$$

$$8 \times 10^{-4} \mathrm{~s}$$

$$3.3 \times 10^{-4} \mathrm{~s}$$

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