1
AP EAPCET 2025 - 27th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$\mathop {\lim }\limits_{x \to {\pi \over 4}} \frac{2 \sqrt{2}-(\cos x+\sin x)^3}{1-\sin 2 x}= $$

A

$\frac{1}{\sqrt{2}}$

B

$\frac{3}{2}$

C

$\frac{3}{\sqrt{2}}$

D

$\frac{\sqrt{3}}{2}$

2
AP EAPCET 2025 - 27th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $[x]$ denote the greatest integer less than or equal to $x$. Then,

$$ \lim _{x \rightarrow 2^{+}}\left(\frac{[x]^3}{3}-\left[\frac{x}{3}\right]^3\right)= $$

A

0

B

$\frac{8}{3}$

C

$\frac{64}{27}$

D

$\frac{1}{3}$

3
AP EAPCET 2025 - 27th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the function $f$ defined by

$$ f(x)=\left\{\begin{array}{cc} \frac{1-\cos 4 x}{x^2}, & x<0 \\ a, & x=0 \\ \frac{\sqrt{x}}{\sqrt{16+\sqrt{x}}-4}, & x>0 \end{array}\right. $$

is continuous at $x=0$, then $a=$

A

1

B

2

C

4

D

8

4
AP EAPCET 2025 - 27th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The domain of the derivative of the function $f(x)=\frac{x}{1+|x|}$ is

A

$[0, \infty)$

B

$(-\infty, 0)$

C

$(-\infty, \infty)$

D

$(0, \infty)$

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