1
COMEDK 2024 Morning Shift
+1
-0

In a single slit diffraction experiment, for slit width '$$\alpha$$' the width of the central maxima is '$$\beta$$'. If we double the slit width then the corresponding width of the central maxima will be:

A
$$4 \beta$$
B
$$\beta$$
C
$$\frac{\beta}{2}$$
D
$$2 \beta$$
2
COMEDK 2023 Morning Shift
+1
-0

In Young's double slit interference experiment, using two coherent waves of different amplitudes, the intensities ratio between bright and dark fringes is 3 . Then, the value of the ratio of the amplitudes of the wave that arrive there is

A
$$\left(\frac{\sqrt{3}+1}{\sqrt{3}-1}\right)$$
B
$$\left(\frac{\sqrt{3}-1}{\sqrt{3}+1}\right)$$
C
$$\sqrt{3}: 1$$
D
$$1: \sqrt{3}$$
3
COMEDK 2023 Morning Shift
+1
-0

In Young's double slit experiment, the ratio of maximum and minimum intensities in the fringe system is $$9: 1$$. The ratio of amplitudes of coherent sources is

A
$$9: 1$$
B
$$3: 1$$
C
$$2: 1$$
D
$$1: 1$$
4
COMEDK 2023 Evening Shift
+1
-0

In the young's double slit experiment the fringe width of the interference pattern is found to be $$3.2 \times 10^{-4} \mathrm{~m}$$, when the light of wave length $$6400^{\circ} \mathrm{A}$$ is used. What will be change in fringe width if the light is replaced with a light of wave length $$4800^{\circ} \mathrm{A}$$

A
$$2.4 \times 10^{-4} \mathrm{~m}$$
B
$$1.6 \times 10^{-4} \mathrm{~m}$$
C
$$0.8 \times 10^{-4} \mathrm{~m}$$
D
$$5.6 \times 10^{-4} \mathrm{~m}$$
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