1
AP EAPCET 2021 - 19th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

If a foot of the normal from the point $$(4,3)$$ to a circle is $$(2,1)$$ and $$2 x-y-2=0$$, is a diameter of the circle, then the equation of circle is

A
$$x^2+y^2+2 x+1=0$$
B
$$x^2+y^2+2 x-1=0$$
C
$$x^2+y^2-2 x-1=0$$
D
$$2\left(x^2+y^2\right)-2 x-1=0$$
2
AP EAPCET 2021 - 19th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

The length of the tangent from any point on the circle $$(x-3)^2+(y+2)^2=5 r^2$$ to the circle $$(x-3)^2+(y+2)^2=r^2$$ is 16 units, then the area between the two circles in square units is

A
$$32 \pi$$
B
$$4 \pi$$
C
$$8 \pi$$
D
$$256 \pi$$
3
AP EAPCET 2021 - 19th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

The equation of the circle, which cuts orthogonally each of the three circles

$$\begin{aligned} & x^2+y^2-2 x+3 y-7=0, \\ & x^2+y^2+5 x-5 y+9=0 \text { and } \\ & x^2+y^2+7 x-9 y+29=0 \end{aligned}$$

A
$$x^2+y^2-16 x-18 y-4=0$$
B
$$x^2+y^2=a^2$$
C
$$x^2+y^2-16 x=0$$
D
$$y^2-x^2+2 x=0$$
4
AP EAPCET 2021 - 19th August Morning Shift
MCQ (Single Correct Answer)
+1
-0

Find the equations of the tangents drawn to the circle $$x^2+y^2=50$$ at the points where the line $$x+7=0$$ meets it.

A
$$7 x+y+50=0$$ and $$7 x-y+50=0$$
B
$$x+y=0$$ and $$x-y=0$$
C
$$x+7 y+5=0$$ and $$y-7 x+5=0$$
D
$$x+7 y+50=0$$ and $$x-7 y+50=0$$
AP EAPCET Subjects
EXAM MAP