AP EAPCET 2024 - 22th May Morning Shift | Circle Question 1 | Mathematics

From a point $(1,0)$ on the circle $x^2+y^2-2 x+2 y+1=0$ if chords are drawn to this circle, then locus of the poles of these chords with respect the circle $x^2+y^2=4$ is

$x=4$

$x+2 y=5$

$x^2+y^2-x-y=0$

$2 y^2=(x+1)$

AP EAPCET 2024 - 22th May Morning Shift

MCQ (Single Correct Answer)

-0

If $A$ and $B$ are the centres of similitude with respect to the circles $x^2+y^2-14 x+6 y+33=0$ and $x^2+y^2+30 x-2 y+1=0$, then mid-point of $A B$ is

$\left(\frac{7}{3}, \frac{4}{5}\right)$

$\left(\frac{3}{2}, \frac{1}{5}\right)$

$\left(\frac{39}{2}, \frac{-7}{4}\right)$

$\left(\frac{39}{4}, \frac{-7}{2}\right)$

AP EAPCET 2024 - 22th May Morning Shift

MCQ (Single Correct Answer)

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$C_1$ is the circle with centre at $O(0,0)$ and radius $4, C_2$ is a variable circle with centre at $(\alpha, \beta)$ and radius 5 . If the common chord of $C_1$ and $C_2$ has slope $\frac{3}{4}$ and of maximum length, then one of the possible values of $\alpha+\beta$ is

$\frac{21}{5}$

$\frac{3}{5}$

$\frac{1}{5}$

$\frac{19}{5}$

AP EAPCET 2024 - 22th May Morning Shift

MCQ (Single Correct Answer)

-0

If the pair of tangents drawn to the circle $x^2+y^2=a^2$ from the point $(10,4)$ are perpendicular. then $a=$

$\sqrt{58}$

$2 \sqrt{63}$

$2 \sqrt{45}$

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