COMEDK 2026 Morning Shift | Liquid Solution Question 7 | Chemistry

At the freezing point of a solution containing a non-volatile solute, the vapour pressure of the liquid solvent becomes less than that of the solid solvent

In case of dissociation of solute particles in a solution, the van't Hoff factor is more than unity because the observed molar mass has a lesser value

The molal boiling point elevation constant for a solvent is directly proportional to its enthalpy of vaporisation

COMEDK 2026 Morning Shift

MCQ (Single Correct Answer)

-0

0.02 M solution of sucrose is isotonic with 0.008 M solution of sodium sulphate. What is the percentage dissociation of the electrolyte?

COMEDK 2025 Evening Shift

MCQ (Single Correct Answer)

-0

An aqueous solution of an electrolyte $\mathrm{A}_3 \mathrm{~B}$ is prepared by dissolving 0.5625 g in 750 ml of water and is found to be $80 \%$ ionised. If $\mathrm{K}_{\mathrm{b}}$ for water is $0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$, calculate the boiling point of the solution at 1.0 atm pressure.

374.33 K

371.68 K

373.18 K

377.2 K

COMEDK 2025 Evening Shift

MCQ (Single Correct Answer)

-0

An aqueous solution of volume V ml contains a non-volatile solute of unknown mass $W_B \mathrm{~g}$ and molar mass $M_B \mathrm{~g} / \mathrm{mol}$. If the Osmotic pressure of the solution is 1.013 bar, which one of the following is the mathematical expression to be used to calculate $W_B$ ?

$W_B=\frac{\pi \mathrm{M}_{\mathrm{B}} V}{760 * \mathrm{RT} * 1000}$

$W_B=\frac{\pi \mathrm{M}_{\mathrm{B}} V 1000}{76 \mathrm{RT}}$

$W_B=\frac{\pi \mathrm{M}_{\mathrm{B}} V}{\mathrm{RT}}$

$W_B=\frac{\pi \mathrm{M}_{\mathrm{B}} V}{1000 \mathrm{RT}}$

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