AP EAPCET 2021 - 20th August Morning Shift | Circle Question 136 | Mathematics

Find the equation of the circle which passes through the point $$(1,2)$$ and the points of intersection of the circles $$x^2+y^2-8 x-6 y+21=0$$ and $$x^2+y^2-2 x-15=0$$

$$x^2+y^2-18 x-12 y+27=0$$

$$2\left(x^2+y^2\right)-18 x-12 y+27=0$$

$$3\left(x^2+y^2\right)-18 x-12 y+27=0$$

$$4\left(x^2+y^2\right)-18 x-12 y+27=0$$

AP EAPCET 2021 - 19th August Evening Shift

MCQ (Single Correct Answer)

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Given, two fixed points $$A(-2,1)$$ and $$B(3,0)$$. Find the locus of a point $$P$$ which moves such that the angle $$\angle A P B$$ is always a right angle.

$$x^2+y^2+x+y+6=0$$

$$x^2+y^2-x-y-6=0$$

$$x+y+6=0$$

$$2 x^2+2 y^2-2 x-2 y+1=0$$

AP EAPCET 2021 - 19th August Evening Shift

MCQ (Single Correct Answer)

-0

The equations of the tangents to the circle $$x^2+y^2=4$$ drawn from the point $$(4,0)$$ are

$$y= \pm \frac{1}{\sqrt{3}}(x-4)$$

$$y= \pm \frac{2}{\sqrt{3}}(x-4)$$

$$x= \pm \frac{1}{\sqrt{3}}(y-4)$$

$$x= \pm \frac{2}{\sqrt{3}}(y-4)$$

AP EAPCET 2021 - 19th August Evening Shift

MCQ (Single Correct Answer)

-0

If $$P(-9,-1)$$ is a point on the circle $$x^2+y^2+4 x+8 y-38=0$$, then find equation of the tangent drawn at the other end of the diameter drawn through $$P$$

$$7 x-3 y=60$$

$$7 x-3 y=56$$

$$7 x+3 y=56$$

$$7 x+3 y=60$$

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