COMEDK 2024 Evening Shift | Haloalkanes and Haloarenes Question 4 | Chemistry

Arrange the compounds $$\mathrm{A}, \mathrm{B}, \mathrm{C}$$ and $$\mathrm{D}$$ in the increasing order of their reactivity towards $$\mathrm{S_N}1$$ reaction.

$$ \begin{aligned} & \mathrm{A}=\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{Cl} \\ & \mathrm{B}=\mathrm{C}_6 \mathrm{H}_5 \mathrm{Cl} \\ & \mathrm{C}=\mathrm{CH}_2=\mathrm{CH}-\mathrm{Cl} \\ & \mathrm{D}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{Cl} \end{aligned}$$

$$\mathrm{D}<\mathrm{B}<\mathrm{A}<\mathrm{C}$$

$$\mathrm{D}<\mathrm{C}<\mathrm{B}<\mathrm{A}$$

$$\mathrm{B}<\mathrm{D}<\mathrm{C}<\mathrm{A}$$

$$\mathrm{C}<\mathrm{A}<\mathrm{D}<\mathrm{B}$$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

Identify the products C, D and F formed in the following sets of reactions.

COMEDK 2024 Evening Shift Chemistry - Haloalkanes and Haloarenes Question 2 English

$$ \mathrm{C}=\mathrm{p} \text {-nitrobromobenzene } \mathrm{D}=\mathrm{m} \text {-nitrobromobenzene } \mathrm{F}=\text { o-nitrobromobenzene } $$

$$ \mathrm{C}=\text { o-nitrobromobenzene } \mathrm{D}=\mathrm{m} \text {-nitrobromobenzene } \quad \mathrm{F}=\mathrm{p} \text {-nitrobromobenzene } $$

$$ \mathrm{C}=\mathrm{o} \text {-nitrobromobenzene } \mathrm{D}=\mathrm{p} \text {-nitrobromobenzene } \mathrm{F}=\mathrm{m} \text {-nitrobromobenzene } $$

$$ \mathrm{C}=\mathrm{m} \text {-nitrobromobenzene } \mathrm{D}=\mathrm{p} \text {-nitrobromobenzene } \mathrm{F}=\text { o-nitrobromobenzene } $$

COMEDK 2024 Afternoon Shift

MCQ (Single Correct Answer)

-0

Arrange the following compounds in the decreasing order of reactivity towards electrophilic substitution reaction.

(I) Chlorobenzene

(II) Nitrobenzene

(III) Benzene

(IV) Isopropylbenzene

$$ \text { IV }>\text { III }>\text { I }>\text { II } $$

$$ \mathrm{I}>\mathrm{II}>\mathrm{IV}>\mathrm{III} $$

$$ \mathrm{IV}>\mathrm{I}>\mathrm{II}>\mathrm{III} $$

$$ \mathrm{III}>\mathrm{II}>\mathrm{IV}>\mathrm{I} $$

COMEDK 2024 Afternoon Shift

MCQ (Single Correct Answer)

-0

Arrange the following in the order of increasing reactivity towards $$\mathrm{SN}_{\mathrm{2}}$$ reactions.

$$\begin{array}{ll} \left(\mathrm{CH}_3\right)_3 \mathrm{CCH}_2 \mathrm{Br}(\mathrm{P}) ; & \\\mathrm{CH}_3\left(\mathrm{CH}_2\right)_3 \mathrm{Br}(\mathrm{Q}) ; &\\ \mathrm{CH}_3 \mathrm{CH}_2-\mathrm{CH}\left(\mathrm{CH}_3\right)-\mathrm{CH}_2 \mathrm{Br}(\mathrm{R}) ; & \\\left(\mathrm{CH}_3\right)_2 \mathrm{CHCH}_2 \mathrm{CH}_2 \mathrm{Br}(\mathrm{S}) \end{array}$$

$$ \mathrm{R}<\mathrm{P}<\mathrm{Q}<\mathrm{S} $$

$$ \mathrm{P}<\mathrm{Q}<\mathrm{R}<\mathrm{S} $$

$$ \mathrm{P}<\mathrm{R}<\mathrm{S}<\mathrm{Q} $$

$$ \mathrm{Q}<\mathrm{S}<\mathrm{R}<\mathrm{P} $$

PREVIOUS NEXT

COMEDK Subjects