COMEDK 2026 Morning Shift | Gravitation Question 4 | Physics

A body is projected vertically upwards from the surface of earth with a velocity ' $v$ ' to reach a height of $10 R$, where $R$ is the radius of the earth, then $v$ is

$\sqrt{\frac{21 \mathrm{gR}}{10}}$

$\sqrt{\frac{21 \mathrm{gR}}{11}}$

$\sqrt{\frac{20 \mathrm{gR}}{11}}$

$\sqrt{\frac{10 \mathrm{gR}}{11}}$

COMEDK 2025 Evening Shift

MCQ (Single Correct Answer)

-0

The unit of universal gravitational constant is :

$\mathrm{N} \mathrm{m}^2 \mathrm{~kg}^2$

$\mathrm{N} \mathrm{m}^{-2} \mathrm{~kg}^{-2}$

$\mathrm{N} \mathrm{m}^{-2} \mathrm{~kg}^2$

$\mathrm{N} \mathrm{m}^2 \mathrm{~kg}^{-2}$

COMEDK 2025 Evening Shift

MCQ (Single Correct Answer)

-0

If the distance between the Sun and Earth is doubled, then the duration of the year on earth will be :

[Given actual duration of the year $=\mathbf{T}$ ]

$2 \sqrt{2} T$

$\frac{T}{2}$

$\sqrt{\mathbf{2}} \boldsymbol{T}$

$\frac{T}{\sqrt{2}}$

COMEDK 2025 Afternoon Shift

MCQ (Single Correct Answer)

-0

The value of universal gravitational constant was first determined by

Newton

Cavendish

Einstein

Galileo

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