Imaginary part of $\frac{(1-i)^3}{(2-i)(3-2 i)}$ is

The square root of $7+24 i$

If $n$ is an integer and $Z=\cos \theta+i \sin \theta, \theta \neq(2 n+1) \frac{\pi}{2}$, then $\frac{1+Z^{2 n}}{1-Z^{2 n}}=$

The complex conjugate of $(4-3 i)(2+3 i)(1+4 i)$ is.