COMEDK 2025 Morning Shift | Liquid Solution Question 4 | Chemistry

For a 1.0 molal solution containing the non-volatile solute Urea, the elevation in boiling point is 2.0 K while the depression in freezing point in a 3.0 molal solution having the same solvent is $4.0 K$. If the ratio $\frac{K_b}{K_f}=\frac{1}{X}$, what is the value of $X$ ?

$\frac{1}{2}$

$\frac{1}{4}$

$\frac{2}{3}$

$\frac{3}{2}$

COMEDK 2025 Morning Shift

MCQ (Single Correct Answer)

-0

Choose the correct statement.

A solution formed by adding Carbon di-sulphide to Acetone forms a maximum boiling azeotrope.

Hypotonic solution is more concentrated with respect to the other solution separated by a semi permeable membrane

For a solvent, $\quad K_b=\frac{R \times M_1 \times T_b^2}{1000 \times \Delta \text { Hvap }}$ $\left(\mathrm{R}=\mathrm{Gas}\right.$ constant, $M_1=$ Molar mass of solvent, $T_b=B \cdot P$ of the solvent $)$

A 1.0 molal solution of Glucose in water is more concentrated than 1.0 M glucose solution in the same solvent.

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

Study the graph between partial pressure and mole fraction of some gases and arrange the gases P, Q, R and S dissolved in H$$_2$$O, in the decreasing order of their K_H values.

COMEDK 2024 Evening Shift Chemistry - Liquid Solution Question 6 English

S > P > R > Q

R > Q > P > S

P > R > S > Q

Q > R > P > S

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

Given that the freezing point of benzene is $$5.48^{\circ} \mathrm{C}$$ and its $$\mathrm{K}_{\mathrm{f}}$$ value is $$5.12{ }^{\circ} \mathrm{C} / \mathrm{m}$$. What would be the freezing point of a solution of $$20 \mathrm{~g}$$ of propane in $$400 \mathrm{~g}$$ of benzene?

$$-0.34^{\circ} \mathrm{C}$$

$$-0.17^{\circ} \mathrm{C}$$

$$-5.8^{\circ} \mathrm{C}$$

$$-0.2{ }^{\circ} \mathrm{C}$$

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