1
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+1
-0

Identify the reagent ' $R$ ' used in the following reaction.

Ketone $\xrightarrow{\mathrm{R}}$ Semicarbazone

A
$\mathrm{NH}_2 \mathrm{OH}$
B
$\mathrm{NH}_2-\mathrm{NH}-\mathrm{CONH}_2$
C
$\mathrm{NH}_2-\mathrm{NH}-\mathrm{C}_6 \mathrm{H}_5$
D
$\quad \mathrm{NH}_2-\mathrm{NH}_2$
2
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+1
-0

Identify substrate ' $A$ ' in the following reaction.

$\mathrm{A}+\mathrm{CO}_2 \xrightarrow[6 \text { atm }]{398 \mathrm{~K}}$ Sodium salicylate $\xrightarrow{\mathrm{H}_3 \mathrm{O}^{+}}$Salicylic acid

A
Phenol
B
Sodium phenoxide
C
Salicyldehyde
D
o-Phenolsulphonic acid
3
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If a random variable X follows the Binomial distribution $B(10, \quad p)$ such that $5 \mathrm{P}(\mathrm{X}=0)=\mathrm{P}(\mathrm{X}=1)$, then the value of $\frac{\mathrm{P}(\mathrm{X}=5)}{\mathrm{P}(\mathrm{X}=6)}$ is equal to

A
$\frac{6}{5}$
B
$\frac{2}{5}$
C
$\frac{12}{5}$
D
$\frac{1}{5}$
4
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+2
-0

A particular solution of $\frac{\mathrm{d} y}{\mathrm{~d} x}=(x+9 y)^2$, when $x=0, y=\frac{1}{27}$ is

A
$\quad 3 x+27 y=\tan \left[3\left(x+\frac{\pi}{12}\right)\right]$
B
$\quad 3 x+27 y=\tan \left(x+\frac{\pi}{4}\right)$
C
$3 x+27 y=\tan \left(x+\frac{\pi}{12}\right)$
D
$3 x+27 y=\tan \left[3\left(x+\frac{\pi}{4}\right)\right]$
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