MHT CET 2025 21st April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

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Water rises up to height ' $x$ ' in a capillary tube immersed vertically in water. When the whole arrangement is taken to a depth ' $d$ ' in a mine, the water level rises up to height Y . If R is the radius of the earth then the ratio $\mathrm{Y}: \mathrm{x}$ is

$\quad \mathrm{R}:(\mathrm{R}+\mathrm{d})$

$\mathrm{R}:(\mathrm{R}-\mathrm{d})$

$\mathrm{R}:(\mathrm{R}-\mathrm{d})^2$

$\mathrm{R}:(\mathrm{R}+\mathrm{d})^2$

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

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In Young's double slit experiment, in an interference pattern, a minimum is observed exactly in front of one slit. The distance between the two coherent sources is d and $\mathrm{D}_{\text { }}$ is the distance between source and screen. The possible wavelengths used are proportional to

$\frac{1}{\mathrm{D}}, \frac{1}{5 \mathrm{D}}, \frac{1}{7 \mathrm{D}}$,

$\frac{1}{\mathrm{D}}, \frac{1}{3 \mathrm{D}}, \frac{1}{5 \mathrm{D}}$,

$\frac{1}{\mathrm{D}}, \frac{1}{2 \mathrm{D}}, \frac{1}{3 \mathrm{D}}$,

$\quad \frac{1}{\mathrm{D}^2}, \frac{1}{2 \mathrm{D}^2}, \frac{1}{3 \mathrm{D}^2}$,

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

-0

The total energy of a circularly orbiting satellite is

half the kinetic energy of the satellite.

half the potential energy of the satellite.

twice the kinetic energy of the satellite.

twice the potential energy of the satellite.