1
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A simple pendulum has time period ' $\mathrm{T}_1$ '. The point of suspension is now moved upward according to equation $\mathrm{y}=\mathrm{kt}^2$ where $\mathrm{k}=1 \mathrm{~m} / \mathrm{s}^2$. If new time period is ' $\mathrm{T}_2$ ' then $\mathrm{T}_1^2 / \mathrm{T}_2^2$ will be ( $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )

A
$2 / 3$
B
$5 / 6$
C
$6 / 5$
D
$3 / 2$
2
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+1
-0

To manufacture a solenoid of length ' $l$ ' and inductance ' $L$ ', the length of the thin wire required is (Diameter of the solenoid is very less than length, $\mu_0=$ permeability of free space)

A
$\left[\frac{4 \pi l L}{\mu_0}\right]^{\frac{1}{2}}$
B
$\left[\frac{2 \pi l}{\mu_0 \mathrm{~L}}\right]^{\frac{1}{2}}$
C
$\left[\frac{4 \pi \mu_0}{l \mathrm{~L}}\right]^{\frac{1}{2}}$
D
$\left[\frac{2 \pi \mu_0 \mathrm{~L}}{l}\right]^{\frac{1}{2}}$
3
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+1
-0

An engine operating between temperatures $T_1$ and $T_2$ has efficiency $\frac{1}{5}$. When $T_2$ is lowered by 45 K , its efficiency becomes $\frac{1}{2}$. Temperatures $T_1$ and $T_2$ are respectively

A
$100 \mathrm{~K}, 70 \mathrm{~K}$
B
$160 \mathrm{~K}, 120 \mathrm{~K}$
C
$140 \mathrm{~K}, 110 \mathrm{~K}$
D
$150 \mathrm{~K}, 120 \mathrm{~K}$
4
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+1
-0

In an n-p-n transistor amplifier, the collector current is 8 mA . If $80 \%$ of the electrons from the emitter reach the collector, then ( $\alpha$ and $\beta$ are current ratios)

A
the base current is 20 mA .
B
the emitter current is 2 mA .
C
$\alpha=0.8, \beta=4.0$
D
$\alpha=4.0, \beta=0.8$
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