MHT CET 2025 21st April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

-0

$\int \sqrt{x^2-6 x-16} \mathrm{~d} x$ equals

$\left(\frac{x-3}{2}\right) \sqrt{x^2-6 x-16} +\frac{5}{2} \log \left(x-3+\sqrt{x^2-6 x-16}\right)+c$

where c is the constant of integration

$$ \begin{aligned} & \left(\frac{x-3}{2}\right) \sqrt{x^2-6 x-16} -\frac{25}{2} \log \left(x-3+\sqrt{x^2-6 x-16}\right)+c \end{aligned} $$

where c is the constant of integration

$\left(\frac{x-3}{2}\right) \sqrt{x^2-6 x-16}+\frac{25}{2} \log \left(x-3+\sqrt{x^2-6 x-16}\right)+c $

where c is the constant of integration

$$ \begin{aligned} \left(\frac{x-3}{2}\right) \sqrt{x^2-6 x-16} & -\frac{5}{2} \log \left(x-3+\sqrt{x^2-6 x-16}\right)+c \end{aligned} $$

where $c$ is the constant of integration

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

-0

The value of $2 \tan ^{-1} \frac{1}{2}+\tan ^{-1} \frac{3}{8}$ is

$\tan ^{-1}\left(\frac{42}{24}\right)$

$2 \tan ^{-1}\left(\frac{42}{24}\right)$

$\tan ^{-1}\left(\frac{24}{41}\right)$

$\tan ^{-1}\left(\frac{41}{12}\right)$

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

-0

With usual notation, in triangle ABC , $\mathrm{m} \angle \mathrm{A}=30^{\circ}$ then the value of $\left(1+\frac{\mathrm{a}}{\mathrm{c}}+\frac{\mathrm{b}}{\mathrm{c}}\right)\left(1+\frac{\mathrm{c}}{\mathrm{b}}-\frac{\mathrm{a}}{\mathrm{b}}\right)$ is equal to

$\frac{2+\sqrt{3}}{2}$

$2+\sqrt{3}$

$\frac{1+\sqrt{3}}{2}$

$1+\sqrt{3}$

MHT CET 2025 21st April Morning Shift

MCQ (Single Correct Answer)

-0

The greatest possible number of points of intersection of 8 distinct straight lines and 4 distinct circles is

104

$\quad{ }^{12} \mathrm{C}_2$

$\quad{ }^4 \mathrm{C}_2$

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