1
GATE ME 2006
MCQ (Single Correct Answer)
+2
-0.6
In a four-bar linkage, $$S$$ denotes the shortest link length, $$L$$ is the longest link length, $$P$$ and $$Q$$ are the lengths of other two links. At least one of the three moving links will rotate by $${360^ \circ }$$ if
A
$$S + L \le P + Q$$
B
$$S + L > P + Q$$
C
$$S + P \le L + Q$$
D
$$S + P > L + Q$$
2
GATE ME 2006
MCQ (Single Correct Answer)
+2
-0.6
A planetary gear train has four gears and one carrier. Angular velocities of the gears are $${\omega _1},{\omega _2},{\omega _3},$$ and $${\omega _4}$$ respectively. The carrier rotates with angular velocity $${\omega _5}.$$ GATE ME 2006 Theory of Machines - Gears and Gear Trains Question 16 English

For $${{\omega _1} = 60}$$ rpm clockwise $$(CW)$$ when looked from the left, what is the angular velocity of the carrier and its direction so that Gear $$4$$ rotates in counter clockwise $$(CCW)$$ direction at twice the angular velocity of Gear $$1$$ when looked from the left?

A
$$130$$ rpm, $$CW$$
B
$$223$$ rpm, $$CCW$$
C
$$256$$ rpm, $$CW$$
D
$$156$$ rpm, $$CCW$$
3
GATE ME 2006
MCQ (Single Correct Answer)
+2
-0.6
Match the items in column $$I$$ and $$II$$

List $$I$$
$$P.$$ Higher kinematic pair
$$Q.$$ Lower kinematic pair
$$R.$$ Quick return mechanism
$$S.$$ Mobility of a linkage

List $$II$$
$$1.$$ Grubler's equation
$$2.$$ Line contact
$$3.$$ Euler's equation
$$4.$$ planar
$$5.$$ Shaper
$$6.$$ Surface contact

A
$$P = 2,Q = 6,R = 4,S = 3$$
B
$$P = 6,Q = 2,R = 4,S = 1$$
C
$$P = 6,Q = 2,R = 5,S = 3$$
D
$$P = 2,Q = 6,R = 5,S = 1$$
4
GATE ME 2006
MCQ (Single Correct Answer)
+2
-0.6
A planetary gear train has four gears and one carrier. Angular velocities of the gears are $${\omega _1},{\omega _2},{\omega _3},$$ and $${\omega _4}$$ respectively. The carrier rotates with angular velocity $${\omega _5}.$$ GATE ME 2006 Theory of Machines - Gears and Gear Trains Question 17 English

What is the relation between the angular velocities of Gear $$1$$ and Gear $$4$$?

A
$${{{\omega _1} - {\omega _5}} \over {{\omega _4} - {\omega _5}}} = 6$$
B
$${{{\omega _4} - {\omega _6}} \over {{\omega _1} - {\omega _5}}} = 6$$
C
$${{{\omega _1} - {\omega _2}} \over {{\omega _4} - {\omega _5}}} = - \left( {{2 \over 3}} \right)$$
D
$${{{\omega _2} - {\omega _5}} \over {{\omega _4} - {\omega _5}}} = - \left( {{8 \over 9}} \right)$$