1
GATE ME 2006
MCQ (Single Correct Answer)
+2
-0.6
Match the items in columns $$I$$ and $$II$$

Column $$I$$
$$P.$$ Addendum
$$Q.$$ Instantaneous center of velocity
$$R.$$ Section modulus
$$S.$$ Prince circle

Column $$II$$
$$1.$$ Cam
$$2.$$ Beam
$$3.$$ Linkage
$$4.$$ Gear

A
$$P = 4,Q = 2,R = 3,S = 1$$
B
$$P = 4,Q = 3,R = 2,S = 1$$
C
$$P = 3,Q = 2,R = 1,S = 4$$
D
$$P = 3,Q = 4,R = 1,S = 2$$
2
GATE ME 2006
MCQ (Single Correct Answer)
+2
-0.6
A planetary gear train has four gears and one carrier. Angular velocities of the gears are $${\omega _1},{\omega _2},{\omega _3},$$ and $${\omega _4}$$ respectively. The carrier rotates with angular velocity $${\omega _5}.$$ GATE ME 2006 Theory of Machines - Gears and Gear Trains Question 13 English

What is the relation between the angular velocities of Gear $$1$$ and Gear $$4$$?

A
$${{{\omega _1} - {\omega _5}} \over {{\omega _4} - {\omega _5}}} = 6$$
B
$${{{\omega _4} - {\omega _6}} \over {{\omega _1} - {\omega _5}}} = 6$$
C
$${{{\omega _1} - {\omega _2}} \over {{\omega _4} - {\omega _5}}} = - \left( {{2 \over 3}} \right)$$
D
$${{{\omega _2} - {\omega _5}} \over {{\omega _4} - {\omega _5}}} = - \left( {{8 \over 9}} \right)$$
3
GATE ME 2006
MCQ (Single Correct Answer)
+2
-0.6
A planetary gear train has four gears and one carrier. Angular velocities of the gears are $${\omega _1},{\omega _2},{\omega _3},$$ and $${\omega _4}$$ respectively. The carrier rotates with angular velocity $${\omega _5}.$$ GATE ME 2006 Theory of Machines - Gears and Gear Trains Question 12 English

For $${{\omega _1} = 60}$$ rpm clockwise $$(CW)$$ when looked from the left, what is the angular velocity of the carrier and its direction so that Gear $$4$$ rotates in counter clockwise $$(CCW)$$ direction at twice the angular velocity of Gear $$1$$ when looked from the left?

A
$$130$$ rpm, $$CW$$
B
$$223$$ rpm, $$CCW$$
C
$$256$$ rpm, $$CW$$
D
$$156$$ rpm, $$CCW$$
4
GATE ME 2006
MCQ (Single Correct Answer)
+2
-0.6
If $${C_f}$$ is the coefficient of speed fluctuation of a flywheel then the ratio of $${\omega _{\max }}/{\omega _{\min }}$$ will be
A
$${{1 - 2{C_f}} \over {1 + 2{C_f}}}$$
B
$${{2 - {C_f}} \over {2 + {C_f}}}$$
C
$${{1 - 2{C_f}} \over {1 - 2{C_f}}}$$
D
$${{2 + {C_f}} \over {2 - {C_f}}}$$
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