GATE EE 2011 | GATE EE Year Wise Previous Years Questions

GATE EE 2011

MCQ (Single Correct Answer)

-0.6

A three–bus network is shown in the figure below indicating the p.u. impedances of each element GATE EE 2011 Power System Analysis - Load Flow Studies Question 12 English

GATE EE 2011 Power System Analysis - Load Flow Studies Question 12 English

The bus admittance matrix, $$Y$$-$$bus,$$ of the network is

$$j\left[ {\matrix{ {0.3} & { - 0.2} & 0 \cr { - 0.2} & {0.12} & {0.08} \cr 0 & {0.08} & {0.02} \cr } } \right]$$

$$j\left[ {\matrix{ { - 15} & 5 & 0 \cr 5 & {7.5} & { - 12.5} \cr 0 & { - 12.5} & {2.5} \cr } } \right]$$

$$j\left[ {\matrix{ {0.1} & {0.2} & 0 \cr {0.2} & {0.12} & { - 0.08} \cr 0 & { - 0.08} & {0.10} \cr } } \right]$$

$$j\left[ {\matrix{ { - 10} & 5 & 0 \cr 5 & {7.5} & {12.5} \cr 0 & {12.5} & { - 10} \cr } } \right]$$

GATE EE 2011

MCQ (Single Correct Answer)

-0.3

A point Z has been plotted in the complex plane, as shown in figure below. GATE EE 2011 Signals and Systems - Continuous and Discrete Time Signals Question 11 English

GATE EE 2011 Signals and Systems - Continuous and Discrete Time Signals Question 11 English

The plot of the complex number $$y=\frac1z$$ is

GATE EE 2011 Signals and Systems - Continuous and Discrete Time Signals Question 11 English Option 1

GATE EE 2011 Signals and Systems - Continuous and Discrete Time Signals Question 11 English Option 2

GATE EE 2011

MCQ (Single Correct Answer)

-0.3

Given two continuous time signals $$x\left(t\right)=e^{-t}$$ and $$y\left(t\right)=e^{-2t}$$ which exist for t > 0, the convolution z(t) = x(t)*y(t) is

$$e^{-t}-e^{-2t}$$

$$e^{-3t}$$

$$e^{+t}$$

$$e^{-t}\;+\;e^{-2t}$$

GATE EE 2011

MCQ (Single Correct Answer)

-0.3

A low–pass filter with a cut-off frequency of 30 Hz is cascaded with a high-pass filter with a cut-off frequency of 20 Hz. The resultant system of filters will function as

an all-pass filter

an all-stop filter

an band stop (band-reject) filter

a band–pass filter

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