GATE EE 2011 | GATE EE Year Wise Previous Years Questions

GATE EE 2011

MCQ (Single Correct Answer)

-0.3

Given two continuous time signals $$x\left(t\right)=e^{-t}$$ and $$y\left(t\right)=e^{-2t}$$ which exist for t > 0, the convolution z(t) = x(t)*y(t) is

$$e^{-t}-e^{-2t}$$

$$e^{-3t}$$

$$e^{+t}$$

$$e^{-t}\;+\;e^{-2t}$$

GATE EE 2011

MCQ (Single Correct Answer)

-0.3

The fourier series expansion $$$f\left(t\right)\;=\;a_0\;+\;\sum_{n=1}^\infty a_n\cos\;n\omega t\;+\;b_n\sin\;n\omega t$$$ of the periodic signal shown below will contain the following nonzero terms GATE EE 2011 Signals and Systems - Continuous Time Periodic Signal Fourier Series Question 24 English

GATE EE 2011 Signals and Systems - Continuous Time Periodic Signal Fourier Series Question 24 English

$$a_0\;and\;b_n\;,\;n=1,\;3,\;5,\;..............\infty$$

$$a_0\;and\;a_n\;,\;n=1,\;2,\;3,\;..............\infty$$

$$a_0\;,\;a_n\;and\;b_n\;,\;n=1,\;2,\;3,\;..............\infty$$

$$a_0\;and\;a_n\;,\;n=1,\;3,\;5,\;..............\infty$$

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