1
GATE EE 2011
MCQ (Single Correct Answer)
+1
-0.3
A three-phase current source inverter used for the speed control of an induction motor is to be realized using MOSFET switches as shown below. Switches $${S_1}$$ to $${S_6}$$ are identical switches. GATE EE 2011 Power Electronics - Inverters Question 30 English

The proper configuration for realizing switches $${S_1}$$ to $${S_6}$$ is

A
GATE EE 2011 Power Electronics - Inverters Question 30 English Option 1
B
GATE EE 2011 Power Electronics - Inverters Question 30 English Option 2
C
GATE EE 2011 Power Electronics - Inverters Question 30 English Option 3
D
GATE EE 2011 Power Electronics - Inverters Question 30 English Option 4
2
GATE EE 2011
MCQ (Single Correct Answer)
+2
-0.6
A voltage commutated chopper circuit, operated at $$500Hz,$$ is shown below. If the maximum value of load current is $$10A,$$ then the maximum current through the main $$(M)$$ and auxiliary $$(A)$$ thyristors will be GATE EE 2011 Power Electronics - Choppers and Commutation Techniques Question 32 English
A
$${i_{M\max }} = 12\,A$$ and $$\,{i_{A\max }} = 10\,A$$
B
$${i_{M\max }} = 12\,A$$ and $$\,{i_{A\max }} = 2\,A$$
C
$${i_{M\max }} = 10\,A$$ and $$\,{i_{A\max }} = 12\,A$$
D
$${i_{M\max }} = 10\,A$$ and $$\,{i_{A\max }} = 8\,A$$
3
GATE EE 2011
MCQ (Single Correct Answer)
+2
-0.6
A load center of 120 MW derives power from two power stations connected by 220 kV transmission lines of 25 km and 75 km as shown in the figure below. The three generators G1,G2 and G3 are of 100 MW capacity each and have identical fuel cost characteristics. The minimum loss generation schedule for supplying the 120 MW load is GATE EE 2011 Power System Analysis - Power Generation Cost Question 12 English
A
$$P1 = 80\,MW + $$ losses
$$P2 = 20\,MW$$
$$P3 = 20\,MW + $$ losses
B
$$P1 = 60\,MW $$
$$P2 = 30\,MW$$ $$+$$ losses
$$P3 = 30\,MW $$
C
$$P1 = 40\,MW $$
$$P2 = 40\,MW$$
$$P3 = 40\,MW + $$ losses
D
$$P1 = 30\,MW + $$ losses
$$P2 = 45\,MW$$
$$P3 = 45\,MW $$
4
GATE EE 2011
MCQ (Single Correct Answer)
+2
-0.6
Two generator units $$G1$$ and $$G2$$ are connected by $$15$$ $$kV$$ line with a bus at the mid-point as shown below GATE EE 2011 Power System Analysis - Per Unit System Question 4 English
$${G_1} = 250\,\,MVA.\,\,\,15kV,\,\,$$ positive sequence $$X = 25$$% on its own base
$${G_2} = 100\,\,MVA.\,\,\,15kV,\,$$ positive sequence $$X = 10$$% on its own base
$${L_1}$$ and $${L_2}$$ $$= 10$$ $$km,$$ positive sequence $$ X = 0.225$$ $$\,\,\Omega /km$$

In the above system the three-phase fault $$MVA$$ at the bus $$3$$ is

A
$$82.55$$ $$MVA$$
B
$$85.11$$ $$MVA$$
C
$$170.91$$ $$MVA$$
D
$$181.82$$ $$MVA$$