1
AP EAPCET 2022 - 4th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$\lim _\limits{n \rightarrow \infty}\left(\frac{1}{1^5+n^5}+\frac{2^4}{2^5+n^5}+\frac{3^4}{3^5+n^5}+\ldots+\frac{n^4}{n^5+n^5}\right)=$$

A
$$\frac{1}{5} \log 3$$
B
$$\frac{1}{3} \log 5$$
C
$$\frac{1}{2} \log 5$$
D
$$\log \sqrt[5]{2}$$
2
AP EAPCET 2021 - 20th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $$\lim _\limits{x \rightarrow 0}\left(\frac{11 x^3-3 x+4}{13 x^3-5 x^2-7}\right)=\frac{a}{b}$$, then the value of $$a+b$$ equals

A
11
B
13
C
8
D
24
3
AP EAPCET 2021 - 20th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$\lim _\limits{x \rightarrow 1} \frac{(1-x)\left(1-x^2\right) \ldots\left(1-x^{2 n}\right)}{\left\{(1-x)\left(1-x^2\right) \ldots \ldots\left(1-x^n\right)\right\}^2}= $$ _____________, $$\forall n \in N$$

A
$${ }^{2 n} P_n$$
B
$${ }^{2 n} \mathrm{C}$$
C
$$(2 n) !$$
D
$$\frac{(2 n) !}{n !}$$
4
AP EAPCET 2021 - 20th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $$f(x)=\frac{\log _e\left(1+x^2(\tan x)\right)}{\sin x^3}, x \neq 0$$ is to be continuous at $$x=0$$, then $$f(0)$$ must be equal to

A
1
B
0
C
$$\frac{1}{2}$$
D
$$-$$1

AP EAPCET Subjects

Browse all chapters by subject