1
AP EAPCET 2024 - 22th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In a $\triangle A B C$, if $A, B$ and $C$ are in arithmetic progression and $\cos A+\cos B+\cos C=\frac{1+\sqrt{2}+\sqrt{3}}{2 \sqrt{2}}$, then $\tan A$ :

A
$\sqrt{3}$
B
$2+\sqrt{3}$
C
1
D
$2-\sqrt{3}$
2
AP EAPCET 2024 - 22th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

    In $\triangle A B C$, if $b+c: c+a: a+b=7: 8: 9$, then the smaller angle (in radians) of that triangle is

A
$\cos ^{-1}\left(\frac{4}{5}\right)$
B
$\frac{\pi}{3}$
C
$\cos ^{-1}\left(\frac{3}{5}\right)$
D
$\frac{\pi}{4}$
3
AP EAPCET 2024 - 22th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
In $\triangle A B C$, if $(a+c)^2=b^2+3 c a$, then $\frac{a+c}{2 R}=$
A
$\frac{\sqrt{3}}{2}$
B
$\sqrt{3} \cos \left(\frac{A-C}{2}\right)$
C
$\cos \left(\frac{A-C}{2}\right)$
D
$\sin \left(\frac{A-C}{2}\right)$
4
AP EAPCET 2024 - 22th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
In $\triangle A B C$, if $A, B$ and $C$ are in arithmetic progression $\Delta=\frac{\sqrt{3}}{2}$ and $r_1 r_2=r_2 r$, then $R=$
A
$\sqrt{3}$
B
2
C
1
D
$\sqrt{2}$
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