1
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $y=\sin ^{-1} \frac{\sqrt{1+\sin x}+\sqrt{1-\sin x}}{\sqrt{1+\sin x}-\sqrt{1-\sin x}}$ and $\frac{-3 \pi}{2}

A

$-\frac{\left|\operatorname{cosec} \frac{x}{2}\right|}{2 \sqrt{\sin ^2 \frac{x}{2}-\cos ^2 \frac{x}{2}}}$

B

$\frac{\left|\sec \frac{x}{2}\right|}{2 \sqrt{\cos x}}$

C

$\frac{\cos \frac{x}{2}}{2 \sqrt{\cos x}}$

D

$\frac{\cos \frac{x}{2}}{\sqrt{\cos x}}$

2
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\frac{1}{2} \sin ^{-1}\left(\frac{3 \sin 2 \theta}{5+4 \cos 2 \theta}\right)=\tan ^{-1} x$, then $x=$

A

$\tan \frac{\theta}{3}$

B

$\frac{1}{3} \tan \theta$

C

$\tan 3 \theta$

D

$\frac{1}{3} \tan 3 \theta$

3
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\operatorname{sech}^{-1} x=\log 2$ and $\operatorname{cosech}^{-1} y=-\log 3$, then $(x+y)=$

A

$\frac{1}{6}$

B

$\frac{1}{20}$

C

6

D

20

4
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $y=\tan ^{-1}\left(\frac{x}{1+2 x^2}\right)+\tan ^{-1}\left(\frac{x}{1+6 x^2}\right)$, then $\frac{d y}{d x}=$

A

$\frac{4}{16 x^2+1}-\frac{3}{9 x^2+1}$

B

$\frac{3}{9 x^2+1}-\frac{1}{x^2+1}$

C

$\frac{3}{9 x^2+1}-\frac{2}{4 x^2+1}$

D

$\frac{1}{9 x^2+1}-\frac{1}{x^2+1}$

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