1
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \tan \left(2 \tan ^{-1}\left(\frac{1}{3}\right)+\tan ^{-1}\left(\frac{1}{7}\right)\right)= $$

A

$\frac{1}{\sqrt{3}}$

B

$\sqrt{3}$

C

1

D

$3 / 7$

2
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \tanh ^{-1}\left(\frac{1}{3}\right)+\operatorname{coth}^{-1}(3)= $$

A

$\operatorname{sech}^{-1}\left(\frac{1}{3}\right)$

B

$\operatorname{cosech}^{-1}\left(\frac{1}{3}\right)$

C

$\cosh ^{-1}\left(\frac{4}{3}\right)$

D

$\sinh ^{-1}\left(\frac{3}{4}\right)$

3
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $y=\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)$ and $\left(\frac{d^2 y}{d x^2}\right)_{x=2}=k$, then $25 k=$

A

$(-3)^2$

B

$(-2)^3$

C

3

D

$(-2)^5$

4
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $f(x)=\sec ^{-1}\left(\frac{1}{2 x^2-1}\right)$ and $g(x)=\tan ^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)$, then the derivative of $f(x)$ with respect to $g(x)$ is

A

$\frac{1+x^2}{4 \sqrt{1-x^2}}$

B

$\frac{\left(1-x^2\right)}{4 \sqrt{1+x^2}}$

C

$-\frac{4\left(1-x^2\right)}{\sqrt{1+x^2}}$

D

$-\frac{4\left(1+x^2\right)}{\sqrt{1-x^2}}$

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