COMEDK 2024 Evening Shift | Atoms and Nuclei Question 4 | Physics

An electron has a mass of $$9.1 \times 10^{-31} \mathrm{~kg}$$. It revolves round the nucleus in a circular orbit of radius $$0.529 \times 10^{-10} \mathrm{~m}$$ at a speed of $$2.2 \times 10^6 \mathrm{~ms}^{-1}$$. The magnitude of its angular momentum is

$$1.06 \times 10^{-34} \mathrm{Kg} \mathrm{m}^2 \mathrm{~s}^{-1}$$

$$1.06 \times 10^{-24} \mathrm{Kg} \mathrm{m}^2 \mathrm{~s}^{-1}$$

$$2.06 \times 10^{-34} \mathrm{Kg} \mathrm{m}^2 \mathrm{~s}^{-1}$$

$$2.06 \times 10^{-24} \mathrm{Kg} \mathrm{m}^2 \mathrm{~s}^{-1}$$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

$$ \text { If the nuclear radius of }{ }^{27} \mathrm{Al} \text { is } 3.6 \text { fermi, the nuclear radius of }{ }^{125} \mathrm{Fe} \text { is } $$

$$6 \times 10^{-10} \mathrm{~m}$$

$$6 \times 10^{-13} \mathrm{~m}$$

$$6 \times 10^{-15} \mathrm{~m}$$

$$6 \times 10^{-12} \mathrm{~m}$$

COMEDK 2024 Morning Shift

MCQ (Single Correct Answer)

-0

The ratio of the radii of the nucleus of two element $$\mathrm{X}$$ and $$\mathrm{Y}$$ having the mass numbers 232 and 29 is:

4 : 1

1 : 4

1 : 2

2 : 1

COMEDK 2024 Morning Shift

MCQ (Single Correct Answer)

-0

The closest approach of an alpha particle when it make a head on collision with a gold nucleus is $$10 \times 10^{-14} \mathrm{~m}$$, then the kinetic energy of the alpha particle is :

3640 J

3.64 J

$$ 3.64 \times 10^{-16} \mathrm{~J} $$

$$ 3.64 \times 10^{-13} \mathrm{~J} $$

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