1
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \sum\limits_{k=1}^n k(k+1)(k+2) \ldots(k+r-1)= $$

A

$\frac{n(n+1)(n+2) \ldots(n+r)}{r+1}$

B

$\frac{n(n+1)(n+2) \ldots(n+r-1)}{r}$

C

$\frac{n(n+1)(n+2) \ldots(n+r+1)}{r+1}$

D

$\frac{n(n+1)(n+2) \cdot \cdot 2 n}{2 n+1}$

2
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

For all $n \in N, \frac{3^n-1}{2} \geq$

A

$n^2\left(2^{\frac{n}{2}}\right)$

B

$n^2\left(3^{\frac{n-1}{2}}\right)$

C

$n^3\left(3^{\frac{n-1}{2}}\right)$

D

$n\left(3^{\frac{n-1}{2}}\right)$

3
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $2 \cdot 5+5 \cdot 9+8 \cdot 13+11 \cdot 17+\ldots$ to $n$ terms $=a n^3+b n^2+c n+d$, then $a-b+c-d=$

A

7

B

5

C

-3

D

-1

4
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0
For all $n \in N$, if $1^3+2^3+3^3+\ldots n^3>x$, then a value of $x$ among the following is
A

$\frac{n^2}{4}$

B

$n^2$

C

$n^4$

D

$\frac{n^2(n+1)^2}{4}$

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