1
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If $O(0,0,0), A(3,0,0)$ and $B(0,4,0)$ form a triangle, then the incentre of $\triangle O A B$ is
A
$(0,1,0)$
B
$(0,1,1)$
C
$(1,0,1)$
D
$(1,1,0)$
2
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
In $\triangle A B C$, if $r_1=4, r_2=8$ and $r_3=24$, then $a=$
A
0
B
$\frac{16}{\sqrt{5}}$
C
$16 \sqrt{5}$
D
$\sqrt{5}$
3
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
Match the items of List I with those of List II (here, $\Delta$ denotes the area of $\triangle A B C$ )
List I List II
(A) $$
\sum \cot A
$$
(i) $$
(a+b+c)^2 \frac{1}{4 \Delta}
$$
(B) $$
\sum \cot \frac{A}{2}
$$
(ii) $$
\left(a^2+b^2+c^2\right) \frac{1}{4 \Delta}
$$
(C) If $\tan A: \tan B: \tan C=1: 2: 3$, then $\sin A: \sin B: \sin C=$ (iii) $$
8: 6: 5
$$
(D) $$
\begin{aligned}
&\text { If } \cot \frac{A}{2}: \cot \frac{B}{2}: \cot \frac{C}{2}=3: 7: 9\\
&\text { then } a: b: c=
\end{aligned}
$$
(iv) $$
12: 5: 13
$$
(v) $$
\sqrt{5}: 2 \sqrt{2}: 3
$$
(vi) $$
4 \Delta
$$
$$ \text { Then, the correct match is } $$
A
A-VI, B-I, C-II, D-III
B
A-II, B-I, C-V, D-III
C
A-II, B-VI, C-V, D-I
D
A-VI, B-II, C-I, D-IV
4
AP EAPCET 2024 - 19th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
In a $\triangle A B C$, if $r_1=2 r_2=3 r_3$, then $\sin A: \sin B: \sin C=$
A
$5: 4: 2$
B
$3: 4: 2$
C
$6: 3: 2$
D
$5: 4: 3$
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