If $\int_1^n[x] d x=120$, then $n=$

$\int\limits_{\frac{-1}{24}}^{\frac{1}{24}} \sec x \log \left(\frac{1-x}{1+x}\right) d x=$

If $[x]$ is the greatest integer function, then $\int_0^5[x] d x=$

$\int_0^{\frac{\pi}{2}} \frac{1}{1+\sqrt{\tan x}} d x=$