1
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
A particle starts from rest and moves along the x -axis with a velocity that varies as $\mathrm{v}=\sqrt{100+4 x} \mathrm{~ms}^{-1}$. The acceleration of the particle is:
A
$25 \mathrm{~ms}^{-2}$
B
$5 \mathrm{~ms}^{-2}$
C
$4 \mathrm{~ms}^{-2}$
D
$2 \mathrm{~ms}^{-2}$
2
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
If E is the amplitude of the electric field of the waves starting from the slits in a double slit experiment and $\theta$ is the phase difference between the waves reaching a point on the screen, the ratio of the amplitude of the resultant electric field at that point on the screen to the amplitude at one of the slits is
A
$\cos (\theta)$
B
$2 \cos (\theta)$
C
$\cos \left(\frac{\theta}{2}\right)$
D
$2 \cos \left(\frac{\theta}{2}\right)$
3
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
Two simple harmonic motions are represented by equations $y_1=0.5 \sin \left[200 \pi \mathrm{t}+\frac{\pi}{3}\right]$ and $y_1=0.5 \cos \pi \mathrm{t}$. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is :
A
$\frac{\pi}{2}$
B
$\frac{\pi}{6}$
C
$\frac{-\pi}{6}$
D
$\frac{-\pi}{2}$
4
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
A vertical spring of spring constant $24 \mathrm{Nm}^{-1}$ is fixed on a table. A ball of mass 0.5 kg at a height 2 m above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance of 50 cm . The net work done in the process is:
A
6.5 J
B
10.5 J
C
12.5 J
D
9.5 J
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