GATE EE 1999 | GATE EE Year Wise Previous Years Questions

GATE EE 1999

MCQ (Single Correct Answer)

-0.6

The logic function $$f = \overline {\left( {x.\overline y } \right) + \left( {\overline x .y} \right)} $$ is the same as

$$f = \left( {x + y} \right)\left( {\overline x + \overline y } \right)$$

$$f = \overline {\left( {\overline x + \overline y } \right) + \left( {x + y} \right)} $$

$$f = \left( {\overline x .\overline y } \right) + \left( {\overline x .\overline y } \right)$$

None of $$(A),(B),(C)$$

GATE EE 1999

MCQ (Single Correct Answer)

-0.6

For a flip-flop formed from two $$NAND$$ gates as shown in figure. The unusable state corresponds to GATE EE 1999 Digital Electronics - Logic Gates Question 9 English

GATE EE 1999 Digital Electronics - Logic Gates Question 9 English

$$X = 0,\,\,Y = 0$$

$$X = 0,\,\,Y = 1$$

$$X = 1,\,\,Y = 0$$

$$X = 1,\,\,Y = 1$$

GATE EE 1999

MCQ (Single Correct Answer)

-0.3

For the circuit shown in Figure, the capacitance measured between terminals $$B$$ and $$Y$$ will be GATE EE 1999 Electric Circuits - Network Elements Question 35 English

GATE EE 1999 Electric Circuits - Network Elements Question 35 English

$${C_C} + \left( {{C_S}/2} \right)$$

$${C_S} + \left( {{C_c}/2} \right)$$

$$\left( {{C_S} + 3{C_c}} \right)/2$$

$$3{C_c} + 2{C_s}$$

GATE EE 1999

MCQ (Single Correct Answer)

-0.6

When a periodic triangular voltage peak amplitude $$1$$ $$V$$ and frequency $$0.5$$ $$Hz$$ is applied to a parallel combination of $$1\,\Omega $$ resistance and $$1$$ $$F$$ capacitance, the current through the voltage source has wave-form

GATE EE 1999 Electric Circuits - Network Elements Question 26 English Option 1

GATE EE 1999 Electric Circuits - Network Elements Question 26 English Option 2

GATE EE 1999 Electric Circuits - Network Elements Question 26 English Option 3

GATE EE 1999 Electric Circuits - Network Elements Question 26 English Option 4

PREVIOUS NEXT

GATE EE Papers

2024