1
GATE EE 1999
MCQ (Single Correct Answer)
+2
-0.6
The function corresponding to the Bode plot of Figure, is GATE EE 1999 Control Systems - Polar Nyquist and Bode Plot Question 33 English
A
$$A = jf/{f_{_1}}$$
B
$$A = 1/\left( {1 - j{f_1}/f} \right)$$
C
$$A = 1/\left( {1 + j{f_1}/f} \right)$$
D
$$A = 1 + jf/{f_1}$$
2
GATE EE 1999
MCQ (Single Correct Answer)
+2
-0.6
For a dual $$ADC$$ type $$3\,{\raise0.5ex\hbox{$\scriptstyle 1$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}}$$ digit $$DVM$$, the reference voltage is $$100$$ $$mV$$ and the first integration time is set to $$300$$ $$ms$$. For some input voltage, the ''deintegration'' period is $$370.2ms.$$ The $$DVM$$ will indicate.
A
$$123.4$$
B
$$199.9$$
C
$$100.0$$
D
$$1.414$$
3
GATE EE 1999
Subjective
+2
-0
The logic function $$F = AC + ABD + ACD$$ is to be realized using an $$8$$ to $$1$$ multiplexer shown in figure, using $$A, C$$ and $$D$$ as control inputs. GATE EE 1999 Digital Electronics - Combinational Circuits Question 10 English

$$(a)$$ Indicate the inputs to be applied at the terminals $$0$$ to $$7.$$
$$(b)$$ Can the function be realize using a $$4$$ to $$1$$ multiplexer?
State YES or NO.

4
GATE EE 1999
MCQ (Single Correct Answer)
+2
-0.6
The logic function $$f = \overline {\left( {x.\overline y } \right) + \left( {\overline x .y} \right)} $$ is the same as
A
$$f = \left( {x + y} \right)\left( {\overline x + \overline y } \right)$$
B
$$f = \overline {\left( {\overline x + \overline y } \right) + \left( {x + y} \right)} $$
C
$$f = \left( {\overline x .\overline y } \right) + \left( {\overline x .\overline y } \right)$$
D
None of $$(A),(B),(C)$$
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