1
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

When the mass attached to a spring is increased from 4 kg to 9 kg , the time period of oscillation increases by $0.2 \pi \mathrm{~s}$. Then, the spring constant of the spring is

A

$80 \mathrm{~N}-\mathrm{m}^{-1}$

B

$200 \mathrm{~N}-\mathrm{m}^{-1}$

C

$50 \mathrm{~N}-\mathrm{m}^{-1}$

D

$100 \mathrm{~N}-\mathrm{m}^{-1}$

2
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The kinetic energy of a particle executing simple harmonic motion at a displacement of 3 cm from the mean position is 4 mJ . If the amplitude of the particle is 5 cm , then the maximum force acting on the particle is

A

0.25 N

B

0.50 N

C

0.75 N

D

1.25 N

3
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A body of mass 1 kg is attached to the lower end of a vertically suspended spring of force constant $600 \mathrm{~N}-\mathrm{m}^{-1}$. If another body of mass 0.5 kg moving vertically upward hits the suspended body with a velocity $3 \mathrm{~ms}^{-1}$ and embedded in it, then the frequency of the oscillation is

A

$\frac{5}{\pi} \mathrm{~Hz}$

B

$\frac{10}{\pi} \mathrm{~Hz}$

C

$\frac{\pi}{5} \mathrm{~Hz}$

D

$\pi \mathrm{Hz}$

4
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the displacement $y$ (in cm ) of a particle executing simple harmonic motion is given by the equation $y=5 \sin (3 \pi t)+5 \sqrt{3} \cos (3 \pi t)$, then the amplitude of the particle is

A

5 cm

B

$5(1+\sqrt{3}) \mathrm{cm}$

C

$5 \sqrt{3} \mathrm{~cm}$

D

10 cm

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