1
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A 3 kg block is connected as shown in the figure. Spring constants of two springs $k_1$ and $k_2$ are $50 \mathrm{Nm}^{-1}$ and $150 \mathrm{Nm}^{-1}$ respectively. The block is released from rest with the springs unstretched. The acceleration of the block in its lowest position is $\left(g=10 \mathrm{~ms}^{-2}\right)$

AP EAPCET 2024 - 20th May Morning Shift Physics - Simple Harmonic Motion Question 5 English
A
$10 \mathrm{~ms}^{-2}$
B
$12 \mathrm{~ms}^{-2}$
C
$8 \mathrm{~ms}^{-2}$
D
$8.8 \mathrm{~ms}^{-2}$
2
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
In a time of 2 s , the amplitude of a damped oscillator becomes $\frac{1}{e}$ times, its initial amplitude $A$. In the next two second, the amplitude of the oscillator is
A
$\frac{1}{2 \theta}$
B
$\frac{2}{e}$
C
$\frac{1}{e^2}$
D
$\frac{2}{e^2}$
3
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
A particle is executing simple harmonic motion with a time period of 3 s . At a position where the displacement of the particle is $60 \%$ of its amplitude. The ratio of the kinetic and potential energies of the particle is
A
$5: 3$
B
$16: 9$
C
$4: 3$
D
$25: 9$
4
AP EAPCET 2024 - 19th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The displacement of a particle executing simple harmonic motion is $y=A \sin (2 t+\phi) \mathrm{m}$, where $t$ is time in second and $\phi$ is phase angle. At time $t=0$, the displacement and velocity of the particle are 2 m and $4 \mathrm{~ms}^{-1}$. The phase angle, $\phi=$
A
$60^{\circ}$
B
$30^{\circ}$
C
$45^{\circ}$
D
$90^{\circ}$
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