1
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The angular frequency of a block of mass 0.1 kg oscillating with the help of a spring of force constant $2.5 \mathrm{~N}-\mathrm{m}^{-1}$ is

A

$02 \mathrm{rad} \mathrm{s}^{-1}$

B

$5 \mathrm{rad} \mathrm{s}^{-1}$

C

$10 \mathrm{rad} \mathrm{s}^{-1}$

D

$2 \mathrm{rad} \mathrm{s}^{-1}$

2
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

As shown in the figure, two blocks of masses $m_1$ and $m_2$ are connected to spring of force constant $k$. The blocks are slightly displaced in opposite directions to $x_1, x_2$ distances and released. If the system executes simple harmonic motion, then the frequency of oscillation of the system ( $\omega$ ) is

AP EAPCET 2024 - 23th May Morning Shift Physics - Simple Harmonic Motion Question 20 English
A
$\left(\frac{1}{m_1}+\frac{1}{m_2}\right) k^2$
B
$\sqrt{\left(\frac{1}{m_1}+\frac{1}{m_2}\right) k^2}$
C
$\sqrt{\left(\frac{1}{m_1}+\frac{1}{m_2}\right)}$
D
$\sqrt{\left(\frac{1}{m_1}+\frac{1}{m_2}\right) k}$
3
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
A mass $M$, attached to a horizontal spring executes simple harmonic motion with amplitude $A_1$. When mass $M$ passes mean position, then a smaller mass millis attached to it and both of them together executing simple harmonic motion with amplitude $A_2$. Then, value of $\frac{A_1}{A_2}$ is
A
$\sqrt{\frac{m^2+M^2}{M^2}}$
B
$\sqrt{\frac{m+M}{M^2}}$
C
$\sqrt{\frac{m+M}{M}}$
D
$$ \text { } \frac{m+M}{M} $$
4
AP EAPCET 2024 - 22th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The displacement of a particle of mass 2 g executing simple harmonic motion is $x=8 \cos \left(50 t+\frac{\pi}{12}\right) \mathrm{m}$, where $t$ is time in second. The maximum kinetic energy of the particle is

A
160 J
B
80 J
C
40 J
D
20 J

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