1
AP EAPCET 2024 - 22th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The displacement of a particle of mass 2 g executing simple harmonic motion is $x=8 \cos \left(50 t+\frac{\pi}{12}\right) \mathrm{m}$, where $t$ is time in second. The maximum kinetic energy of the particle is

A
160 J
B
80 J
C
40 J
D
20 J
2
AP EAPCET 2024 - 22th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The relation between the force ( $F$ in Newton) acting on a particle executing simple harmonic motion and the displacement of the particle ( $y$ in metre) is $500 F+\pi^2 y=0$. If the mass of the particle is 2 g . The time period of oscillation of the particle is
A
8 s
B
6 s
C
2 s
D
4 s
3
AP EAPCET 2024 - 22th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two simple harmonic motions are represented by $y_1=5[\sin 2 \pi t+\sqrt{3} \cos 2 \pi t]$ and $y_2=5 \sin \left[2 \pi t+\frac{\pi}{4}\right]$. The ratio of their amplitudes is

A
$1: 1$
B
$2: 1$
C
$1: 3$
D
$\sqrt{3}: 1$
4
AP EAPCET 2024 - 22th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

When a mass $m$ is connected individually to the springs $k_1$ and $k_2$, the oscillation frequencies are $v_1$ and $v_2$. If the same mass is attached to the two springs as shown in the figure, the oscillation frequency would be

AP EAPCET 2024 - 22th May Morning Shift Physics - Simple Harmonic Motion Question 5 English
A
$v_1+v_2$
B
$\sqrt{v_1^2+v_2{ }^2}$
C
$\left(\frac{1}{v_1}+\frac{1}{v_2}\right)^{-1}$
D
$\sqrt{v_1{ }^2-v_2{ }^2}$
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