1
AP EAPCET 2025 - 26th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The probability distribution of a random variable $X$ is as follows. Then, the mean of $x$ is

X = X I 1 X = X I 1 X=XI_(1) P ( X = X i ) P X = X i P(X=X_(i))
-2 k 2 3 k 2 3 (k^(2))/(3)
-1 k 2 k 2 k^(2)
0 2 k 2 3 2 k 2 3 (2k^(2))/(3)
1 k 2 k 2 (k)/(2)
2 k 2 k 2 (k)/(2)
A

$\frac{1}{3}$

B

$\frac{1}{5}$

C

$\frac{11}{2}$

D

$\frac{13}{2}$

2
AP EAPCET 2025 - 27th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two students appeared simultaneously for an entrance exam. If the probability that the first student gets qualified in the exam is $\frac{1}{4}$ and the probability that the second student gets qualified in the same exam is $\frac{2}{5}$, then the probability that atleast one of them gets qualified in that exam is

A

$\frac{1}{10}$

B

$\frac{7}{20}$

C

$\frac{6}{10}$

D

$\frac{11}{20}$

3
AP EAPCET 2025 - 27th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

For three events $A, B$ and $C$ of a sample space, $P$ (exactly one of $A$ or $B$ occurs ) $=P$ (exactly one of $B$ or $C$ occurs) $=P($ exactly one of $C$ or $A$ occurs $)=\frac{1}{4}$. If probability of all the three events occurring simultaneously is $\frac{1}{16}$, then the probability that atleast one of the events occur is

A

$\frac{3}{16}$

B

$\frac{5}{16}$

C

$\frac{7}{16}$

D

$\frac{7}{32}$

4
AP EAPCET 2025 - 27th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$A$ bag $P$ contains 4 red and 5 black balls another bag Q contains 3 red and 6 black balls. If one ball is drawn at random from bag $P$ and two balls are drawn from bag $Q$, then the probability that out of the three balls drawn two are black and one is red, is

A

$\frac{25}{54}$

B

$\frac{25}{64}$

C

$\frac{27}{64}$

D

$\frac{35}{54}$

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