1
AP EAPCET 2025 - 26th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The points $(2,3)$ and $\left(-4,-\frac{4}{3}\right)$ lie on the opposite sides of the line $L \equiv 5 x-6 y+k=0$ and k is an integer. If the points $(1,2)$ and $(4,5)$ lie on the same side of the line $L=0$, then the perpendicular distance from origin to the line $L=0$ is

A

$\frac{7}{\sqrt{61}}$

B

$\frac{9}{\sqrt{61}}$

C

$\frac{10}{\sqrt{61}}$

D

$\frac{11}{\sqrt{61}}$

2
AP EAPCET 2025 - 26th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the incentre of the triangle formed by the lines $x-2=0, x+y-1=0, x-y+3=0$ is $(\alpha, \beta)$, then $\beta=$

A

2

B

$\sqrt{2}+1$

C

$\frac{2 \sqrt{2}-1}{\sqrt{2}+1}$

D

4

3
AP EAPCET 2025 - 26th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the equation of the pair of straight lines intersecting at ( $a, b$ ) and perpendicular to the pair of lines $3 x^2-4 x y+5 y^2=0$ is $l x^2+2 n x y+m y^2-32 x-26 y+c=0$, then $\frac{a+b+c}{l+h+m}=$

A

$\frac{38}{5}$

B

$\frac{17}{2}$

C

$\frac{15}{6}$

D

$\frac{49}{6}$

4
AP EAPCET 2025 - 26th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$P Q R$ is a right-angled isosceles triangle with right angle at $P(2,1)$. If the equation of the line $Q R$ is $2 x+y=3$, then the equation representing the pair of lines $P Q$ and $P R$ is

A

$3 x^2-3 y^2-8 x y-10 x-15 y-20=0$

B

$3 x^2-3 y^2+8 x y+20 x+10 y+25=0$

C

$3 x^2-3 y^2+8 x y-20 x-10 y+25=0$

D

$3 x^2-3 y^2+8 x y+10 x+15 y+20=0$

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