1
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The general solution satisfying both the equations $\sin x=-\frac{3}{5}$ and $\cos x=-\frac{4}{5}$ is

A

$x=(2 n+1) \pi+\tan ^{-1}\left(\frac{3}{4}\right), n \in Z$

B

$x=2 n \pi+\tan ^{-1}\left(\frac{3}{4}\right), n \in Z$

C

$x=n \pi+\tan ^{-1}\left(\frac{3}{4}\right), n \in Z$

D

$x=n \pi \pm \tan ^{-1}\left(\frac{3}{4}\right), n \in Z$

2
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The number of solutions of the equation $\sec x \cdot \cos 5 x+1=0$ in the interval $[0,2 \pi]$ is

A

5

B

8

C

10

D

12

3
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $2 \sin x-\cos 2 x=1$, then $\left(3-2 \sin ^2 x\right)=$

A

$\sqrt{3}$

B

$-\sqrt{3}$

C

$\sqrt{5}$

D

$-\sqrt{5}$

4
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $x \neq(2 n+1) \frac{\pi}{4}$, then the general solutions of $\cos x+\cos 3 x=\sin x+\sin 3 x$ is

A

$n \pi+\frac{\pi}{8}$

B

$n \pi \pm \frac{\pi}{8}$

C

$\frac{n \pi}{2} \pm \frac{\pi}{8}$

D

$\frac{n \pi}{2}+\frac{\pi}{8}$

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