$\log (2 x-y)=2 x+C$

$(2 x-y)^3+4 y=C$

$(2 x-y)^3+6 x=C$

$\log (2 x-y)=2 y+C$

$(x-y) \log x+x=C$

$x-y=\frac{x}{\log x}+C$

$y-x=\frac{x}{\log x}+C$

$(y-x) \log x+x=C$

$\cos \left(\frac{y}{x}\right)=\log |x|+C$

$\cos \left(\frac{y}{x}\right)=\frac{1}{x}+C$

$\cos \left(\frac{x}{y}\right)=\log |y|+C$

$\cos \frac{y}{x}=\frac{2}{x}+C$

$y=\tan \left(\frac{x+y}{2}\right)+C$

$y=\sec \left(\frac{x+y}{2}\right)+C$

$y=x \sec \left(\frac{y}{x}\right)+C$

$y=-\cos ^{-1}\left(\frac{y}{x}\right)+C$