AP EAPCET 2021 - 20th August Morning Shift | Straight Lines and Pair of Straight Lines Question 19 | Mathematics

The equation of a straight line which passes through the point $$\left(a \cos ^3 \theta, a \sin ^3 \theta\right)$$ and perpendicular to $$(x \sec \theta+y \operatorname{cosec} \theta)=a$$ is

$$\frac{x}{a}+\frac{y}{b}=a \cos \theta$$

$$x \cos \theta-y \sin \theta=a \cos 2 \theta$$

$$x \cos \theta+y \sin \theta=a \cos 2 \theta$$

$$x \cos \theta+y \sin \theta-a \cos 2 \theta=1$$

AP EAPCET 2021 - 20th August Morning Shift

MCQ (Single Correct Answer)

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The acute angle between lines $$6 x^2+11 x y-10 y^2=0$$ is

$$\tan ^{-1}\left(\frac{\sqrt{361}}{2}\right)$$

$$\tan ^{-1}\left(\frac{\sqrt{361}}{4}\right)$$

$$\tan ^{-1}\left(\frac{361}{2}\right)$$

$$\tan ^{-1}\left(\frac{361}{4}\right)$$

AP EAPCET 2021 - 20th August Morning Shift

MCQ (Single Correct Answer)

-0

If the lines, joining the origin to the points of intersection of the curve $$2 x^2-2 x y+3 y^2+2 x-y-1=0$$ and the line $$x+2 y=k$$, are at right angles, then $$k^2$$ equals

AP EAPCET 2021 - 20th August Morning Shift

MCQ (Single Correct Answer)

-0

The equation of bisector of the angle between the lines represented by $$3 x^2-5 x y+4 y^2=0$$ is

$$9 x^2+6 y^2-2 x=0$$

$$5\left(x^2-y^2\right)=2 x y$$

$$3 x^2+2 x y-y^2=0$$

$$5 x^2+x y+4 y^2=0$$

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