Observe the following reaction,

$$ 2 A_2(g)+B_2(g) \xrightarrow{T(\mathrm{~K})} 2 A_2 B(g)+600 \mathrm{~kJ} $$

The standard enthalpy of formation $\left(\Delta_f H^{\ominus}\right)$ of $A_2 B(g)$ is

Identify the molecule for which the enthalpy of atomisation ( $\Delta_a H^{\ominus}$ ) and bond dissociation enthalpy $\left(\Delta_{\text {bond }} H^{\ominus}\right)$ are not equal

Given below are two statements :

Statement I For isothermal irreversible change of an ideal gas, $q=-w=p_{\text {ext }}\left(V_{\text {final }}-V_{\text {initial }}\right)$

Statement II For adiabatic change, $\Delta U=w_{\text {adiabatic }}$

The correct answer is :

A thermodynamic process $(B \rightarrow E)$ was completed as shown below. The work done is equal to area under the limits