At 300 K , the vapour prssures of $A$ and $B$ liquids are 500 and 400 mm Hg respectively. Equal moles of $A$ and $B$ are mixed to form an ideal solution. The mole fraction of $A$ and $B$ in vapour state is respectively

Two statements are given below

Statements I : Liquids $A$ and $B$ form a non-ideal solution with positive deviation. The interactions between $A$ and $B$ are weaker than $A-A$ and $B-B$ interactions.

Statements II : For an ideal solution $\Delta_{\text {mix }} H=0$; $\Delta_{\text {mix }} V=0$

The correct answer is

At 290 K , a vessel (I) contains equal moles of three liquids $(A, B, C)$. The boiling points of $A, B$ and $C$ are $350 \mathrm{~K}, 373 \mathrm{~K}$ and 308 K respectively. Vessel (I) is heated to 300 K and vapours were collected into vessel (II). Identify the correct statements. (Assume vessel (I) contains liquids and vapours and vessel (II)contains only vapours)

(I) Vessel - I is rich in liquid $B$

(II) Vessel - II is rich in vapour of $C$

(III) The vapour pressures of $A, B, C$ in vessel (I) at 290 K follows the order $C>A>B$

At $300 \mathrm{~K}, 6 \mathrm{~g}$ of urea was dissolved in 500 mL of water. What is the osmotic pressure (in atm) of resultant solution?

$$ \begin{aligned} & \left(R=0.082 \mathrm{~L}^{\operatorname{atm~K}}{ }^{-1} \mathrm{~mol}^{-1}\right) \\ & (\mathrm{C}=12 ; \mathrm{N}=14 ; \mathrm{O}=16 ; \mathrm{H}=1) \end{aligned} $$