1
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the equation of motion of a projectile is $y=A x-B x^2$, then the ratio of the maximum height reached and the range of the projectile is

A

$\frac{A}{4}$

B

$\frac{A}{B}$

C

$\frac{B}{4}$

D

$\frac{A^2}{B}$

2
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The height of ceiling in an auditorium is 30 m . A ball is thrown with a speed of $30 \mathrm{~ms}^{-1}$ from the entrance such that it just moves very near to the ceiling without touching it and then it reaches the ground at the end of the auditorium. Then, the length of auditorium is [Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ ]

A

$60 \sqrt{2} \mathrm{~m}$

B

$30 \sqrt{2} \mathrm{~m}$

C

$70 \sqrt{2} \mathrm{~m}$

D

$100 \sqrt{2} \mathrm{~m}$

3
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A particle crossing the origin at time $t=0$ moves in the $X Y$-plane with a constant acceleration ' $a$ ' in $y$-direction. If the equation of motion of the particle is $y=b x^2$ (where $b$ is a constant), then its velocity component in the $x$-direction is

A

$\sqrt{\frac{2 b}{a}}$

B

$\sqrt{\frac{a}{2 b}}$

C

$\sqrt{\frac{a}{b}}$

D

$\sqrt{\frac{b}{a}}$

4
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If a ball projected vertically upwards with certain initial velocity from the ground crosses a point at a height of 25 m twice in a time interval of 4 s , then the initial velocity of the ball is

(Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )

A

$20 \mathrm{~ms}^{-1}$

B

$30 \mathrm{~ms}^{-1}$

C

$40 \mathrm{~ms}^{-1}$

D

$25 \mathrm{~ms}^{-1}$

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