AP EAPCET 2024 - 18th May Morning Shift | Motion in a Plane Question 8 | Physics

Object is projected such that it has to attain maximum range. Another body is projected to reach maximum heigh. If both the objects reached the same maximum height, then the ratio of initial velocities

$2: 1$

$\sqrt{2} : 1$

$1: \sqrt{2}$

$1: 2$

AP EAPCET 2024 - 18th May Morning Shift

MCQ (Single Correct Answer)

-0

Ball is projected at an angle of $45^{\circ}$ with the horizontal．It passes through a wall of height $h$ at a horizontal distance $d_1$ from the point of profection and strikes the ground at a distance $d_1+d_2$ from the point of projection, then $h$ is :

$h=\frac{2 d d_2}{d_1+d_2}$

$h=\frac{d d_2}{d_1+d_2}$

$h=\frac{\sqrt{2} d d_2}{d_1+d_2}$

$h=\frac{d d_2}{2\left(d_1+d_2\right)}$

AP EAPCET 2024 - 18th May Morning Shift

MCQ (Single Correct Answer)

-0

second after projection，a projectile is travelling in a direction inclined at $45^{\circ}$ to horizontal．After two more seconds，it is travelling horizontally．Then，the magnitude of velocity of the projectile is $\left(g=10 \mathrm{~ms}^{-2}\right)$

$10 \sqrt{13} \mathrm{~ms}^{-1}$

$11 \mathrm{~ms}^{-1}$

$10 \sqrt{2} \mathrm{~ms}^{-1}$

$20 \mathrm{~ms}^{-1}$

AP EAPCET 2022 - 5th July Morning Shift

MCQ (Single Correct Answer)

-0

A projectile is launched from the ground, such that it hits a target on the ground which is 90 m away. The minimum velocity of projectile to hit the target is (acceleration due to gravity $$=10 \mathrm{~ms}^{-2}$$)

$$10 \mathrm{~ms}^{-1}$$

$$16 \mathrm{~ms}^{-1}$$

$$60 \mathrm{~ms}^{-1}$$

$$30 \mathrm{~ms}^{-1}$$

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