AP EAPCET 2025 - 21st May Evening Shift | Motion in a Plane Question 12 | Physics

A car is moving with a velocity of $4 \mathrm{~ms}^{-1}$ towards east. After a time of 4 s , if it is heading north-east with a velocity of $4 \sqrt{2} \mathrm{~ms}^{-1}$, then the average velocity of the car is

$2 \sqrt{5} \mathrm{~ms}^{-1}$

$3 \sqrt{5} \mathrm{~ms}^{-1}$

$4 \sqrt{3} \mathrm{~ms}^{-1}$

$5 \sqrt{3} \mathrm{~ms}^{-1}$

AP EAPCET 2025 - 21st May Evening Shift

MCQ (Single Correct Answer)

-0

A body of mass 5 kg starts from the origin with an initial velocity $(30 \hat{\mathbf{i}}+40 \hat{\mathbf{j}}) \mathrm{ms}^{-1}$. If a constant force $-(\hat{\mathbf{i}}+5 \hat{\mathbf{j}}) \mathrm{N}$ acts on the body, then the time in which the $y$-component of its velocity becomes zero is

5 s

20 s

40 s

80 s

AP EAPCET 2025 - 21st May Morning Shift

MCQ (Single Correct Answer)

-0

If bullets are fired in all possible directions from same point with equal velocity of $10 \mathrm{~ms}^{-1}$ and with an angle of projection $45^{\circ}$, then the area covered by the bullets on the ground is nearly (Acceleration due to gravity $=10 \mathrm{~m} \mathrm{~s}^{-2}$ )

$628 \mathrm{~m}^2$

$314 \mathrm{~m}^2$

$157 \mathrm{~m}^2$

$79 \mathrm{~m}^2$

AP EAPCET 2025 - 21st May Morning Shift

MCQ (Single Correct Answer)

-0

A ball is projected from a point with a speed $V_0$ at certain angle with the horizontal. From the same point and at the same instant, a person starts running with a constant speed $0.5 V_0$ to catch the ball. If the person catches the ball after some time, then the angle of projection of the ball is

$60^{\circ}$

$30^{\circ}$

$45^{\circ}$

$53^{\circ}$

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