If the range of a body projected with a velocity of $60 \mathrm{~ms}^{-1}$ is $180 \sqrt{3} \mathrm{~m}$, then the angle of projection of the body is

(Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )

If the height of a projectile at a time of 2 s from the beginning of motion is 60 m , then the time of flight of the projectile is

(Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )

The angle of projection of a projectile whose path is shown in the given figure is

If the equation of motion of a projectile is $y=A x-B x^2$, then the ratio of the maximum height reached and the range of the projectile is